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NEW QUESTION: 1
Your network contains two servers named Hyper1 and Hyper2 that run Windows Server 2012. Hyper1 and Hyper2 have the Hyper-V server role installed and are members of a failover cluster named Cluster1.
The network contains a Fibre Channel Storage Area Network (SAN) named SAN1. SAN1 contains a LUN named LUN1. You plan to host a new virtual machine named VM1 on Cluster1. You need to ensure that VM1 can store data directly on LUN1.
What three actions should you perform?

Answer:
Explanation:

Explanation

Box 1: Configure Hyper1 and Hyper2 to connect to LUN1
Box 2: Create a Virtual Fibre Channel SAN on Hyper1 Hyper2
Box 3: Create a Fibre Channel adapter on VM1
References: https://technet.microsoft.com/en-us/library/dn551169%28v=ws.11%29.aspx?

NEW QUESTION: 2
What mechanism does asymmetric cryptography use to secure data?
A. an MD5 hash
B. a public/private key pair
C. shared secret keys
D. an RSA nonce
Answer: B
Explanation:
Explanation/Reference:
Explanation:
Asymmetric cryptography, also known as public key cryptography, uses public and private keys to encrypt and decrypt data. The keys are simply large numbers that have been paired together but are not identical (asymmetric). One key in the pair can be shared with everyone; it is called the public key. The other key in the pair is kept secret; it is called the private key. Either of the keys can be used to encrypt a message; the opposite key from the one used to encrypt the message is used for decryption.
Reference: http://searchsecurity.techtarget.com/definition/asymmetric-cryptography

NEW QUESTION: 3
Examine the Data Guard configuration:
DGMGRL > show configuration;
Configuration-Animals
Protection Mode: MaxPerformance
Databases:
dogs-Primary database
sheep-Snapshot standby database
cats-Snapshot standby database
Fast-Start Failover: DISABLED
Configuration Status:
SUCCESS
You receive an error while attempting to raise the protection mode to Maximum Availability:
DGMGDRL> edit configuration set protection mode as maxavailability;
Error: ORA-16627: operation disallowed since no standby databases would remain to support protection mode
Failed.
Identify two statements that you can execute, either one of which will enable successful raising of the protection mode to Maximum Availability.
A. DGMGRL> convert database cats to physical standby;
B. DGMGRL> edit database dogs set property LogXptMode= fastsync;
C. DGMGRL> edit database sheep set property LogXptMode= fastsync;
D. DGMGRL> edit database cats set property LogXptMode= sync;
E. DGMGRL> convert database sheep to physical standby;
Answer: A,D
Explanation:
Explanation/Reference:
The MAXAVAILABILITY protection mode requires that there be at least one standby database configured to use standby redo log files, with its LogXptMode configurable database property set to SYNC.
References: https://docs.oracle.com/cd/B28359_01/server.111/b28295/cli.htm