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NEW QUESTION: 1
A. Option C
B. Option B
C. Option D
D. Option A
Answer: B
Explanation:
Explanation
NAT operation is typically transparent to both the internal and external hosts. Typically the internal host is aware of the true IP address and TCP or UDP port of the external host. Typically the NAT device may function as the default gateway for the internal host. However the external host is only aware of the public IP address for the NAT device and the particular port being used to communicate on behalf of a specific internal host.
NAT and TCP/UDP
"Pure NAT", operating on IP alone, may or may not correctly parse protocols that are totally concerned with IP information, such as ICMP, depending on whether the payload is interpreted by a host on the "inside" or
"outside" of translation. As soon as the protocol stack is traversed, even with such basic protocols as TCP and UDP, the protocols will break unless NAT takes action beyond the network layer.
IP packets have a checksum in each packet header, which provides error detection only for the header. IP datagrams may become fragmented and it is necessary for a NAT to reassemble these fragments to allow correct recalculation of higher-level checksums and correct tracking of which packets belong to which connection.
The major transport layer protocols, TCP and UDP, have a checksum that covers all the data they carry, as well as the TCP/UDP header, plus a "pseudo-header" that contains the source and destination IP addresses of the packet carrying the TCP/UDP header. For an originating NAT to pass TCP or UDP successfully, it must recompute the TCP/UDP header checksum based on the translated IP addresses, not the original ones, and put that checksum into the TCP/UDP header of the first packet of the fragmented set of packets. The receiving NAT must recompute the IP checksum on every packet it passes to the destination host, and also recognize and recompute the TCP/UDP header using the retranslated addresses and pseudo-header. This is not a completely solved problem. One solution is for the receiving NAT to reassemble the entire segment and then recompute a checksum calculated across all packets.
The originating host may perform Maximum transmission unit (MTU) path discovery to determine the packet size that can be transmitted without fragmentation, and then set the t fragment (DF) bit in the appropriate packet header field. Of course, this is only a one-way solution, because the responding host can send packets of any size, which may be fragmented before reaching the NAT.
NEW QUESTION: 2
A network engineer is configuring an OSPFv2 neighbor adjacency Drag and drop the parameters from the left onto their required categories on the right. Not all parameters are used
Answer:
Explanation:
NEW QUESTION: 3
次のうち、効果的な外部情報セキュリティコミュニケーション計画の最も重要な要素はどれですか？
A. 広報の関与
B. コミュニケーションディレクターの承認
C. 規制遵守
D. 上級管理職の承認
Answer: C
NEW QUESTION: 4
If the primary purpose of a tariff is to completely eliminate the price advantage of foreign competition, it will be expected to:
A. raise either a large or a small amount of revenue depending on the magnitude of the tariff imposed.
B. raise an amount of revenue equal to the amount of the tariff multiplied by the volume of exports.
C. raise a relatively small amount of tax revenue.
Answer: C
Explanation:
Since the volume of imports will either be zero or very small, tax revenues will also be small.