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NEW QUESTION: 1
SAP BW / 4HANAでBWクエリを開発するために何が使用されますか？
A. BEx Web Application Designer
B. BEx Query Designer
C. SAP Analysis for Microsoft Office
D. Eclipse-based Query Designer
Answer: D

NEW QUESTION: 2
You are designing an Extract, Transform and Load (ETL) solution that loads data into dimension tables. The ETL process involves many transformation steps.
You need to ensure that the design can provide:
* Auditing information for compliance and business user acceptance
* Tracking and unique identification of records for troubleshooting and error correction
What should you do?
A. Develop a custom data lineage solution.
B. Create a version control repository for the ETL solution.
C. Develop a Data Quality Services (DQS) solution.
D. Develop a Master Data Services (MDS) solution.
Answer: A

NEW QUESTION: 3
シミュレーション
トポロジ図に示されているように、部分的な構成を持ち、RouterCに接続されているマルチレイヤーSwitchCの構成を担当しました。
ホストH1およびH2がサーバーS1に正常にpingできるように、SwitchCを構成する必要があります。また、SwitchCはサーバーS1をpingできる必要があります。
管理上の制限と要件のため、VLANを追加/削除したり、トランクリンクを作成したりしないでください。会社のポリシーでは、静的ルーティングまたはデフォルトルーティングの使用が禁止されています。すべてのルートは、EIGRP 65010ルーティングプロトコルを介して学習する必要があります。
RouteCにアクセスできません。 RouterCが正しく構成されています。 RouterCでトランキングが設定されていません。
可能な場合、ルーテッドインターフェイスはサブネット上の最も低いホストを使用する必要があります。このソリューションを実装するには、次のサブネットを使用できます。
-10.10.10.0/24
-190.200.250.32/27
-190.200.250.64/27
ホストH1とH2は、正しいIPアドレスとデフォルトゲートウェイで構成されています。
SwitchCは、Ciscoをイネーブルパスワードとして使用します。
ルーティングは、図に示されている特定のサブネットに対してのみ有効にする必要があります。
注：管理上の制限と要件のため、VLANを追加または削除したり、VLANポートの割り当てを変更したり、トランクを作成したりしないでください。会社のポリシーでは、静的ルーティングまたはデフォルトルーティングの使用が禁止されています。すべてのルートは、EIGRPルーティングプロトコルを介して学習する必要があります。




A. See the step by step solution:
There are two ways to configure interVLAN routing in this case:
+ Use RouterC as a "router on a stick" and SwitchC as a pure Layer2 switch. Trunking must be established between RouterC and SwitchC . + Only use SwitchC for interVLAN routing without using RouterC, SwitchC should be configured as a Layer 3 switch (which supports ip routing function as a router). No trunking requires.
The question clearly states "No trunking has been configured on RouterC" so RouterC does not contribute to interVLAN routing of hosts H1 & H2 -> SwitchC must be configured as a Layer 3 switch with SVIs for interVLAN routing.
We should check the default gateways on H1 & H2. Click on H1 and H2 and type the "ipconfig" command to get their default gateways.
C:\>ipconfig
We will get the default gateways as follows:
Host1: + Default gateway: 190.200.250.33
Host2: + Default gateway: 190.200.250.65
Now we have enough information to configure SwitchC (notice the EIGRP AS in this case is 650) Note: VLAN2 and VLAN3 were created and gi0/10, gi0/11 interfaces were configured as access ports so we don't need to configure them in this sim.
SwitchC# configure terminal SwitchC(config)# int gi0/1 SwitchC(config)# int vlan 2 SwitchC(config-if)# ip address 190.200.250.33 255.255.255.224 SwitchC(config-if)# no shutdown SwitchC(config-if)# int vlan 3 SwitchC(config-if)# ip address 190.200.250.65 255.255.255.224 SwitchC(config-if)# no shutdown SwitchC(config-if)#exit SwitchC(config)# ip routing (Notice: MLS will not work without this command) SwitchC(config)# router eigrp 650 SwitchC(config-router)# network 10.10.10.0 0.0.0.255 NOTE: THE ROUTER IS CORRECTLY CONFIGURED, so you will not miss within it in the exam , also don't modify/delete any port just do the above configuration. Also some reports said the "no auto-summary" command can't be used in the simulator, in fact it is not necessary because the network 190.200.0.0/16 is not used anywhere else in this topology.
In order to complete the lab, you should expect the ping to SERVER to succeed from the MLS , and from the PCs as well.
Also make sure you use the correct EIGRP AS number (in the configuration above it is 650 but it will change when you take the exam) but we are not allowed to access RouterC so the only way to find out the EIGRP AS is to look at the exhibit above. If you use wrong AS number, no neighbor relationship is formed between RouterC and SwitchC .
In fact, we are pretty sure instead of using two commands "network 190.200.250.32 0.0.0.31″ and "network 190.200.250.64 0.0.0.31″ we can use one simple command "network 190.200.0.0″ because it is the nature of distance vector routing protocol like EIGRP: only major networks need to be advertised; even without "no auto-summary" command the network still works correctly. But after finishing the configuration, we can use "show run" command to verify, only the summarized network 190.200.0.0 is shown.
B. See the step by step solution:
There are two ways to configure interVLAN routing in this case:
+ Use RouterC as a "router on a stick" and SwitchC as a pure Layer2 switch. Trunking must be established between RouterC and SwitchC . + Only use SwitchC for interVLAN routing without using RouterC, SwitchC should be configured as a Layer 3 switch (which supports ip routing function as a router). No trunking requires.
The question clearly states "No trunking has been configured on RouterC" so RouterC does not contribute to interVLAN routing of hosts H1 & H2 -> SwitchC must be configured as a Layer 3 switch with SVIs for interVLAN routing.
We should check the default gateways on H1 & H2. Click on H1 and H2 and type the "ipconfig" command to get their default gateways.
C:\>ipconfig
We will get the default gateways as follows:
Host1: + Default gateway: 190.200.250.33
Host2: + Default gateway: 190.200.250.65
Now we have enough information to configure SwitchC (notice the EIGRP AS in this case is 650) Note: VLAN2 and VLAN3 were created and gi0/10, gi0/11 interfaces were configured as access ports so we don't need to configure them in this sim.
SwitchC# configure terminal SwitchC(config)# int gi0/1 SwitchC(config-if)#no switchport -> without using this command, the simulator does not let you assign IP address on Gi0/1 interface. SwitchC(config-if)# ip address 10.10.10.2 255.255.255.0 ->RouterC has used IP 10.10.10.1 so this is the lowest usable IP address. SwitchC(config-if)# no shutdown SwitchC(config-if)# exit SwitchC(config)# int vlan 2 SwitchC(config-if)# ip address 190.200.250.33 255.255.255.224 SwitchC(config-if)# no shutdown SwitchC(config-if)# int vlan 3 SwitchC(config-if)# ip address 190.200.250.65 255.255.255.224 SwitchC(config-if)# no shutdown SwitchC(config-if)#exit SwitchC(config)# ip routing (Notice: MLS will not work without this command) SwitchC(config)# router eigrp 650 SwitchC(config-router)# network 10.10.10.0 0.0.0.255 SwitchC(config-router)# network 190.200.250.32 0.0.0.31 SwitchC(config-router)# network 190.200.250.64 0.0.0.31 NOTE: THE ROUTER IS CORRECTLY CONFIGURED, so you will not miss within it in the exam , also don't modify/delete any port just do the above configuration. Also some reports said the "no auto-summary" command can't be used in the simulator, in fact it is not necessary because the network 190.200.0.0/16 is not used anywhere else in this topology.
In order to complete the lab, you should expect the ping to SERVER to succeed from the MLS , and from the PCs as well.
Also make sure you use the correct EIGRP AS number (in the configuration above it is 650 but it will change when you take the exam) but we are not allowed to access RouterC so the only way to find out the EIGRP AS is to look at the exhibit above. If you use wrong AS number, no neighbor relationship is formed between RouterC and SwitchC .
In fact, we are pretty sure instead of using two commands "network 190.200.250.32 0.0.0.31″ and "network 190.200.250.64 0.0.0.31″ we can use one simple command "network 190.200.0.0″ because it is the nature of distance vector routing protocol like EIGRP: only major networks need to be advertised; even without "no auto-summary" command the network still works correctly. But in the exam the sim is just a flash based simulator so we should use two above commands, just for sure. But after finishing the configuration, we can use "show run" command to verify, only the summarized network 190.200.0.0 is shown.
Answer: B

NEW QUESTION: 4
You have finished updating and resolving dependencies for some source code. What command should you run before recompiling the code into binary form?
A. make all
B. make clean
C. make install
D. make dep
Answer: B