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NEW QUESTION: 1
Lynne runs a small hotel, and as a value added service for her customers she has implemented a Wi-Fi hot-spot. Lynne has read news articles about how hackers wait at hotspots trying to take advantage of unsuspecting users. She wants to avoid this problem at her hotel.
What is an efficient and practical step that Lynne can take to decrease the likelihood of active attacks on her customers' wireless computers?
A. Implement an SSL VPN in the WLAN controller that initiates after HTTPS login.
B. Require EAP-FAST authentication and provide customers with a username/password on their receipt.
C. Implement Network Access Control (NAC) and require antivirus and firewall software along with OS patches.
D. Enable station-to-station traffic blocking by the access points in the hotel.
Answer: D

NEW QUESTION: 2
You need to manually create a service location (SRV) record for a server that has the Key Management Service (KMS) installed.
Which SRV record should you create?
A. _mskms._tcp.contoso.com
B. _kms._tcp.contoso.com
C. _kms._tcp._msdcs.contoso.com
D. _vlmcs._tcp.contoso.com
Answer: D
Explanation:
Manually Create SRV Records in DNS If the environment does not support DDNS, the SRV RRs must be manually created to publish the KMS host. Environments that do not support DDNS should disable publishing on all KMS hosts to prevent event logs from collecting failed DNS publishing events. To disable auto-publishing, use the Slmgr.vbs script with the /cdns command-line option. See the "Configuring KMS" section for more information about the Slmgr.vbs script. Note Manually created SRV RRs can coexist with SRV RRs that KMS hosts automatically publish in other domains as long as all records are maintained to prevent conflicts. Using DNS Manager, in the appropriate forwarding lookup zone, create a new SRV RR using the appropriate information for the location. By default, KMS listens on TCP port 1688, and the service is _VLMCS. Table 2 contains example settings for a SRV RR. Table 2 SRV Resource Record


NEW QUESTION: 3
Click the Exhibit button.
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT:<1.1.1.100/51303->1.1.1.30/3389;6> matched filter MatchTraffic:
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT:packet [48] ipid = 5015, @423d7e9e Feb 2
09:00:02 09:00:00.1872004:CID-0:RT:---- flow_process_pkt: (thd 1): flow_ctxt type 13, common flag Ox0, mbuf Ox423d7d00
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT: flow process pak fast ifl 72
In_ifp fe-0/0/7.0
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT: fe-0/0/7.0:1.1.1.100/51303- >1.1.1.30/3389, top, flag 2 syn
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT: find flow: table Ox5258d7b0, hash
17008(Oxffff), sa 1.1.1.100, da 1.1.1.30, sp 51303, dp 3389, proto 6, tok
448
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT: no session found, start first path. in_tunnel - 0, from_cp_flag - 0
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT: flow_first_create_session
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT: flow first_in_dst_nat: in <fe-0/0/7.0>, out
< N/A> dst_adr 1.1.1.30, sp 51303, dp 3389
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT: chose interface fe-0/0/7.0 as incoming nat if.
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT:flow_first_rule_dst_xlate: packet 1.1.1.100-
> 1.1.1.30 nsp2 0.0.0.0->192.168.224.30.
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT:flow_first_routing: call flow_route_lookup() src_ip 1.1.1.100, x_dst_ip 192.168.224.30, in ifp fe-0/0/7.0, out ifp N/A sp 51303, dp 3389, ip_proto 6, tos 0
Feb 2 09:00:02 09:00:00.1872004:CID-O:RT:Doing DESTINATION addr route-lookup Feb
2 09:00:02 09:00:00.1872004:CID-0:RT: routed (x_dst_ip 192 168.224.30)
from untrust (fe-0/0/7.0 in 0) to ge-0/0/0.0, Next-hop: 192.168.224.30
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT: policy search from zone untrust-> zone trust
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT: policy has timeout 900
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT: app 0, timeout 1800s, curr ageout 20s
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT:flow_first_src_xlate: src nat 0.0.0.0(51303) to
192.168.224.30(3389) returns status 1, rule/pool id 1/2. Feb 2 09:00:02
09:00:00.1872004:CID-0:RT: dip id = 2/0, 1.1.1.100/51303->192.168.224.3/48810
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT: choose interface ge-0/0/0.0 as outgoing phy if
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT:is_loop_pak: No loop: on ifp: ge-0/0/0.0, addr:
192.168.224.30, rtt_idx:0
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT:sm_flow_interest_check: app_id 0, policy 9, app_svc_en 0, flags Ox2. not interested
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT:sm_flow_interest_check: app_id 1, policy 9, app_svc_en 0, flags Ox2. not interested
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT:flow_first_service_lookup():
natp(Ox51ee4680): app_id, 0(0).
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT: service lookup identified service O.
Referring to the exhibit, which two statements are correct? (Choose two.)
A. Source NAT is being used.
B. The incoming interface is fe-0/0/7.
C. This traffic matches an existing flow.
D. The packet being inspected is a UDP packet.
Answer: B,C