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NEW QUESTION: 1
Which choices below are roles or responsibility of the person
designated to manage the contingency planning process? Select three
A. Providing stress reduction programs to employees after an event
B. Providing direction to senior management
C. Ensuring the identification of all critical business functions
D. Integrating the planning process across business units
Answer: B,C,D
Explanation:
Contingency planners have many roles and responsibilities when planning business continuity, disaster recovery, emergency management, or business resumption processes. In addition to correct answers some of these roles and responsibilities can include: Ensuring executive management compliance with the contingency plan program Providing periodic management reports and status Coordinating and integrating the activation of emergency response organizations Answer "Providing stress reduction programs to employees after an event", providing stress reduction programs to employees after an event, is a responsibility of the human resources area. Source: Contingency Planning and Management, Contingency Planning 101, by Kelley Goggins, March 1999.
NEW QUESTION: 2
You need to ensure that only valid parameters are passed to the EditLog action.
How should you build the route? (To answer, drag the appropriate code segments to the correct location or locations. Each code segment may be used once, more than once, or not at all. You may need to drag the split bar between panes or scroll to view content.)
Answer:
Explanation:
Explanation
NEW QUESTION: 3
You are faced with a counting problem in which you must choose k objects from n total objects. The order of choosing does not matter. The counting method you should use is:
A. The binomial formula.
B. None of these answers is correct.
C. The multinomial formula.
D. The multiplication rule.
Answer: A
Explanation:
Explanation/Reference:
Explanation:
The combination, or binomial formula, gives the number of ways that k objects can be chosen from n items, without regard to the order of choosing. The formula is n_C_k = (n choose k) = n! / [k! *(n-k)!].