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NEW QUESTION: 1
Which of the following could cause a Denial of Service (DoS) against an authentication system?
A. Hashing of audit logs
B. Encryption of audit logs
C. Remote access audit logs
D. No archiving of audit logs
Answer: D
NEW QUESTION: 2
A. CustNo
B. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo
C. CustNoWHERE D.CustNo IS NULL
D. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
E. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
F. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR L.CustNo IS NULL
G. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
H. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
I. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
J. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo
Answer: F
Explanation:
SQL Server provides the full outer join operator, FULL OUTER JOIN, which includes all rows from both tables, regardless of whether or not the other table has a matching value.
Consider a join of the Product table and the SalesOrderDetail table on their ProductID columns. The results show only the Products that have sales orders on them. The ISO FULL OUTER JOIN operator indicates that all rows from both tables are to be included in the results, regardless of whether there is matching data in the tables.
You can include a WHERE clause with a full outer join to return only the rows where there is no matching data between the tables. The following query returns only those products that have no matching sales orders, as well as those sales orders that are not matched to a product.
USE AdventureWorks2008R2;
GO
-- The OUTER keyword following the FULL keyword is optional.
SELECT p.Name, sod.SalesOrderID
FROM Production.Product p
FULL OUTER JOIN Sales.SalesOrderDetail sod
ON p.ProductID = sod.ProductID
WHERE p.ProductID IS NULL
OR sod.ProductID IS NULL
ORDER BY p.Name ;
References: https://technet.microsoft.com/en-us/library/ms187518(v=sql.105).aspx
NEW QUESTION: 3
会社は最近、レガシーインフラストラクチャプロビジョニングスクリプトをAWS CloudFormationテンプレートに変換しました。新しく開発されたテンプレートは、会社のプライベートGitHubリポジトリでホストされます。 CloudFortmationを採用して以来、同社はCloudFormationテンプレートの更新に関するいくつかの問題に遭遇し、実行を引き起こしたり、環境管理を作成したりしてエラーの増加を懸念しており、ソリューションアーキテクトにCloudFortmationテンプレート更新の自動テストの設計を依頼しています。
これらの要件を満たすために、ソリューションアーキテクチャは何をすべきですか？
A. AWS CodePipelineを使用して、GitHubリポジトリのCloudFormationテンプレートストアから変更セットを作成および実行します。 AWS CodeBuildによって実行されるテストスクリプトを使用してデプロイするCodePipelineアクションを設定します。
B. AWS CodePipelineも使用して、プライベートGitHubリポジトリに保存されているCloudFormationテンプレートから変更セットを作成しますAWS CodeDeployを使用して変更セットを実行します
C. AWS Lambdaを使用してGitHubリポジトリをAWS CodeCommitにミラーリングします。 AWS CodeDeployを使用して、CloudFormationテンプレートから変更セットを作成し、実行します。 AWS CodeBuildによって実行されるテストスクリプトを使用して、CodeDeployにデプロイメントをテストさせます。
D. AWS Lambdaを使用してGitHubリポジトリをAWS CodeCommitにミラーリングします。 AWS CodeBuildを使用してCloudFormationテンプレートから変更セットを作成して実行し、テストスクリプトでCodeBuildにデプロイをテストさせます
Answer: A
Explanation:
Explanation
https://docs.aws.amazon.com/AWSCloudFormation/latest/UserGuide/continuous-delivery-codepipeline-basic-w