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NEW QUESTION: 1
The joint probability of events A and B occurring equals 0.11. The probability of neither A nor B occurring equals 0.64. If P(A) equals 0.24, the probability of B occurring equals ________.
A. 0.46
B. 0.51
C. 0.29
D. 0.23
Answer: D
Explanation:
Explanation/Reference:
Explanation:
We are given that P(neither A nor B) = 0.64, P(A and B) = 0.11 and P(A) = 0.24. The probability of neither A nor B occurring equals one minus the probability of either A or B occurring i.e. P(neither A nor B) = 1 - P (A or B).
Thus, P(A or B) = 1 - P(neither A nor B) = 1 - 0.64 = 0.36.
Now, P(A or B) = P(A) + P(B) - P(A and B)
Therefore, P(B) = P(A or B) - P(A) + P(A and B) = 0.36 - 0.24 + 0.11 = 0.23.
NEW QUESTION: 2
DRAG DROP
Drag the Cisco default administrative distance to the appropriate routing protocol or route. (Not all options are used.)
Answer:
Explanation:
NEW QUESTION: 3
A. Option B
B. Option A
C. Option D
D. Option C
Answer: B