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NEW QUESTION: 1
Sie haben einen Computer mit dem Namen Computer 1, auf dem Windows 10 ausgeführt wird.
Sie aktivieren den Systemschutz und erstellen einen Wiederherstellungspunkt mit dem Namen Point1.
Sie führen folgende Änderungen durch:
* Fügen Sie dem Desktop vier Dateien mit den Namen File1.txt, File2.dll, File3.sys und File4.exe hinzu.
Führen Sie ein Konfigurationsskript aus, das die folgenden vier Registrierungsschlüssel hinzufügt:
- Key1 to HKEY_CURRENT_USER
- Key2 to HKEY_CLASSES_ROOT
- Key3 to HKEY_LOCAL_MACHINE\SYSTEM
- Key4 to HKEY_CURRENT_CONFIG
Sie stellen Point1 wieder her.
Welche Dateien und Registrierungsschlüssel werden entfernt? Wählen Sie zum Beantworten die entsprechenden Optionen im Antwortbereich aus.
HINWEIS: Jede richtige Auswahl ist einen Punkt wert.
Answer:
Explanation:
Explanation:
References:
https://www.maketecheasier.com/what-system-restore-can-and-cannot-do-to-your-windows-system/
https://superuser.com/questions/343112/what-does-windows-system-restore-exactly-back-up-and-restore
NEW QUESTION: 2
Click the Exhibit button.
A provider of MPLS services configures MPLS Layer-3 VPN services for two customers. Each customer has three branch offices that will be interconnected by MPLS Layer-3 VPNs. The address blocks chosen by the customers for each site are shown in the following chart:
The provider uses OSPF as its IGP with the Loopback 0 addresses shown as the OSPF router-id and the MPLS LSR-ID. A traceroute from Cust-A Site #1 to Cust-A Site #2 displays 5 intermediate routers.Which statements are true? (Select three.)
A. TTL propagation is enabled on PE-1.
B. MPLS label TTL expires on P-10.
C. All but the first trace is processed by PE-2.
D. IP TTL expires on P-20.
E. TTL propagation is disabled on PE-1.
F. PE-1 generates ICMP echo replies on behalf of P-10 and P-20.
Answer: A,B,C
NEW QUESTION: 3
コードの断片を考えます：
7行目に挿入すると、100を印刷できるようになるコード断片はどれですか。
A. Function<Integer> funRef = e -> e + 10;
Integer result = funRef.apply(value);
B. ToIntFunction<Integer> funRef = e -> e + 10;
int result = funRef.applyAsInt (value);
C. ToIntFunction funRef = e -> e + 10;
int result = funRef.apply (value);
D. IntFunction funRef = e -> e + 10;
Integer result = funRef.apply (10);
Answer: A